Bond order of $N - O$ bonds in nitrate ion is:

1.33

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1.25

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1.50

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1

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Solution

The correct option is A $1.33$
$Bond order = \frac{Total number of bonds in a molecule}{Total number of resonating structures}$

$Resonating structures of N O_{3}^{-}$ :
$\Rightarrow Bond order = \frac{4}{3} = 1.33$

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