Calculate the heat of combustion -kJ- of propane- - C - 3 H - 8- using the listed standard enthalpy of reaction data- nbsp- nbsp- nbsp- nbsp- nbsp- - C - 3 H - 8 - g - -5 O - 2 - g - - 3C O - 2 - g - -4 H - 2 O- g - 3C- s - -4 H - 2 - g - - C - 3 H - 8 - g - nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- H - kJ -103-8- C- s - - O - 2 - g - - C O - 2 - g - nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- - H - kJ -393-5- H - 2 - g - - 1 - 2 O - 2 - g - - H - 2 O- g - nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- H - kJ -241-8-2043-9-1532-9-1021-9-739-1

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Hess' Law

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Question

Calculate the heat of combustion (kJ) of propane, $C_{3} H_{8}$ using the listed standard enthalpy of reaction data:
$C_{3} H_{8} (g) + 5 O_{2} (g) ⟶ 3 C O_{2} (g) + 4 H_{2} O (g)$
$3 C (s) + 4 H_{2} (g) ⟶ C_{3} H_{8} (g) Δ H / k J = - 103.8$
$C (s) + O_{2} (g) ⟶ C O_{2} (g) Δ H / k J = - 393.5$
$H_{2} (g) + 1 / 2 O_{2} (g) ⟶ H_{2} O (g) Δ H / k J = - 241.8$

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2 N_{2} (g) + 5 O_{2} (g) ⟶ 2 N_{2} O_{5} (s)

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2 H_{2} (g) + O_{2} (g) ⟶ 2 H_{2} O (l); Δ H / k J = - 571.6

C_{3} H_{8} (g) + 5 O_{2} (g) \to 3 C O_{2} (g) + 4 H_{2} O (l)

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2 N_{2} (g) + 5 O_{2} (g) ⟶ 2 N_{2} O_{5} (s)

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