Calculate the mass percentage of benzene $\left(C_6{H}_6\right)$ and carbon tetrachloride $\left(CC{l}_4\right)$ if $22g$ of benzene is dissolved in $122g$ of carbon tetrachloride.

In general Mass % of $X=\left[\frac{\text{Mass of X}}{\text{Mass of total mixture}}\right]\times 100$

Mass of the total mixture= $22+122=144g$

Mass % of benzene= $\left(\frac{22}{144}\right)\times 100=15.28$%

Mass % of $CC{l}_4=\left(\frac{122}{144}\right)\times 100=84.72$%