Calculate the mole fraction of Benzene $(C_{6} H_{6})$ in a solution containing 30% by mass in $H C l$ .(Cl = 35.5)

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Solution

$C_{6} H_{6} + H C l$
Let the total mass be $100$ $g r a m$
Mass of $C_{6} H_{6} = 30$ $g m$
Moles of $C_{6} H_{6} = \frac{30}{78} = 0.38$ $m o l e s$
Mass of $H C l = 70$ $g m$
Moles of $H C l = \frac{}{} = 1.92$ $m o l e s$
Mole fraction of $C_{6} H_{6} = \frac{0.38}{1.92 + 0.38} = \frac{0.38}{2.3} = 0.1652$

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