Calculate the number of moles in $128 g$ of $S O_{2}$ :

1mole

No worries! We‘ve got your back. Try BYJU‘S free classes today!

2 mole

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$3 m o l e$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$4 m o l e$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
2 mole

The explanation for correct option:
The molar mass of sulfur is $32 g$ and the molar mass of oxygen is $16 g$ .
Therefore the molar mass of $S O_{2} = 32 + (2 \times 16) = 64 g$
We know the mole number is $\frac{w e i g h t o f S O_{2}}{M o l a r m a s s o f S O_{2}} = \frac{128}{64} = 2 m o l e$
The explanation for the incorrect options:
The given mole number is not correctly representing the mole number of $128 g o f S O_{2}$ .

Suggest Corrections

Similar questions

11.2

{S O}_{2}

The number of mole present in 128 g of oxygen is 16.

S O_{2}

{S O_{4}}^{2 -}

S O_{2}

P - - H_{3}

S - - O_{2}

H N - - O_{3}

H_{3} P - - O_{4}

2 H_{2} S + S O_{2} \to 2 H_{2} O + 3 S

S O_{2}

H_{2} S

Join BYJU'S Learning Program