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Question

Calculate the wavelength for the emission transition if it starts from the orbit having radius 1.3225 nm and ends at the one having 211.6 pm. Name the series to which this transition belongs and the region of the spectrum.

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Solution

The radius of nth orbit of H-like species is given by the expression 0.529n2Z ˚A or 52.9n2Z pm.
r1=1.3225 nm =1322.5 pm =52.9n21Zpm ......(1)
r2=211.6 pm =52.9n22Z pm ......(2)
Dividing (1) by (2), we get
r1r2=1322.5211.6=n21n22
n21n22=6.25 n1n2=2.5
n2=5, n1=2.
The transition is in Balmer series.
¯ν=1.097×107(122152)=1.097×107×0.21 m1
λ=1v=123.037×105=434×109 m or 434 nm
The transition lies in the visible region.

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