Check whether $6^n$ can end with the digit 0 for any natural number n.

TO CHECK: Whether 6ⁿ can end with the digit 0 for any natural number n.

We know that $6^n$ = $(2\ast 3{)}^n$

$6^n$= $2^n$ x $3^n$

Therefore, prime factorization of $6^n$ does not contain 5 and 2 as a factor together. Hence$6^n$can never end with the digit 0 for any natural number n.