Consider an atom of iron represented as ${}_{26}{Fe}^{56}$ . Give the number of protons, electrons, and neutrons present in the atom.

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Solution

The atom of iron is represented as ${}_{26}{Fe}^{56}$ has the atomic number 26 and mass number 56.
The number of electrons in an iron atom is 26.
The number of protons in an iron atom is 26.
The number of neutrons in the nucleus of the iron atom is 56 - 26 = 30.
Hence, ${}_{26}{Fe}^{56}$ contain 26 electrons. 26 protons and 30 neutrons.

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Consider an atom of iron represented asFe5626. Give the number of protons, electrons, and neutrons present in the atom.

Consider an atom of iron represented as ${}_{26}{Fe}^{56}$ . Give the number of protons, electrons, and neutrons present in the atom.