Copper oxide was prepared by 2 different methods in 1 case 1-75 g of metal give 2-19 gram of oxide in case 2 -1-14 gram of metal give 1-43 gram of oxide-how we can illustrate this according to the law of constant proportion

Solution : 1st method : weight of Cu : 1.75 g weight of CuO : 2.19 g Ratio of weight of Cu and CuO = 1.75 : 2.19 = 1 : 0.7990 ≈ 5 : 4 2nd method : weight ...

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Standard IX

Chemistry

Law of Constant Proportions

Copper oxide ...

Question

Copper oxide was prepared by 2 different methods. In case 1, 1.75 g of metal gives 2.19 grams of oxide. In case 2, 1.14 grams of metal gives 1.43 grams of oxide. How we can illustrate this according to the law of constant proportion

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Solution

In case 1, mass of copper = 1.75 g
Mass of copper oxide = 2.19 g
% of copper in the oxide =Mass of copper/Mass of copper oxide×100 = $\frac{1.75}{2.19} \times 100 = 79.9$ %
∴% of oxygen =100−79.9=20.1%
In case 2, the mass of copper = 1.14 g
Mass of copper oxide = 1.43 g
% of copper in the oxide = $\frac{1.14}{1.43} \times 100 = 79.7$ %
% of oxygen = 100 - 79.7 = 20.3 %.
Thus, copper oxide prepared by any of the given methods contains copper and oxygen in the same proportion by mass (with the experimental error). Hence, it proves the law of constant proportions.

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