${(1-x)}^{3/2}$ can be expanded in ascending powers of $x$ if

The correct option is A $-1<x<1$
Given, $(1-x{)}^{\frac{3}{2}}$
$=(1-x)\left[\sqrt{1-x}\right]$
Hence this can only be expanded in powers of x if
$|x|<1$
$\to -1<x<1$