Divide:
(v) 225 by (-15)

Open in App

Solution

Step: Divide $225 b y - 15$
The division of an integer by an integer of opposite signs is always negative.
Dividing 225 by (-15), we have
= $\frac{225}{- 15}$
= $\frac{15 \times 15}{- 15}$
= $- 15$
$∴$ Dividing 225 by $- 15$ gives $- 15$ .

Suggest Corrections

Similar questions

a_{1}, a_{2}, a_{3} \dots

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

a_{1}, a_{2}, a_{3}, . . . . . . . . i s a n A . P . s u c h t h a t a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225

a_{1} + a_{2} + a_{3} + . . . . . . . + a_{23} + a_{24} i s e q u a l t o

24

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24}

225

a_{1}, a_{2}, a_{3}

a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} =

a_{1} + a_{2} + a_{3} + . . . + a_{23} + a_{24} =

If $a_{1}, a_{2}, a_{3} . . . . .$ are in $A . P .$ such that $a_{1} + a_{5} + a_{10} + a_{15} + a_{20} + a_{24} = 225$ .

a_{1} + a_{2} + a_{3} . . . . . . . . . + a_{23} + a_{24}

Join BYJU'S Learning Program