- E-0Zn-2-Zn-0-76V- The EMF of the cell- Zn-Zn-2-1M- - HCl-pH-2- - H-2-1atm- Pt- is - 0-700V- 0-642V- 0-878V- 0-875V-

The correct option is B 0.642V Given log[H^+]=2 ∴ [H]^+=10^ 2 2e^ #160; +Zn^2+ #160; → #160; Zn #160; #160; #160; #160; # ...

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Nernst Equation

E^0Zn^2+/Zn=-...

Question

$E^{0} Z n^{2 +} / Z n = - 0.76 V$ The EMF of the cell
$Z n / Z n^{2 +} (1 M) | | H C l (p H = 2) | H_{2 (1 a t m)}, P t$ is ::

0.878 V

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0.642 V

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0.875 V

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0.700 V

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Solution

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Similar questions

Z n \to Z n^{2 +} + 2 e^{-} (E_{(Z n^{2 +} / Z n)}^{0} = - 0.76 V)

F e \to F e^{2 +} + 2 e^{-} E^{0} = 0.41 V

F e^{2 +} + Z n \to Z n^{2 +} + F e

E^{o}

{Z n}^{2 +} | Z n

- 0.76

Z n ∣ ∣ {Z n}^{2 +} (1 M) ∣ ∣ ∣ ∣ 2 H^{+} (1 M) ∣ ∣ H_{2} (1 a t m)

Z n + 2 H^{+} \to Z n^{2 +} (0.1 M) + H_{2} (1 a t m)

0.28

25^{\circ} C

E_{(Z n^{2 +} | Z n)}^{⊖} = - 0.76 V

Z n (s) / Z n^{2 +} (a q) ∥ C u^{2 +} (a q) / C u (s)

{E^{0}}_{{Z n}^{2 +} / Z n} =

-

{E^{0}}_{{C u}^{2 +} / C u} =

+

{E^{0}}_{c e l l}

K

E^{\circ}

C u_{(s)} + Z n_{(a q)}^{2 +} \to Z n_{(s)} + C u_{(a q)}^{2 +}

E_{C u^{2 +} / C u}^{0} = 0.34 V, E_{Z n^{2 +} / Z n}^{0} = - 0.76 V

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