If a particle is thrown with a velocity u making an angle % with the horizontal, then range R is given by
R = (u2sin2%)/g _____(i)
also the maximum height attained by the particle is given by
h = (u2sin2%)/2g _____(ii)
thus, dividing eq. (ii) by eq. (i),
h/R = [(u2sin2%)/2g] / [(u2sin2%)/g]
= sin2%/sin2%
= sin2%/2sin%cos% [sin2% = 2sin%cos%]
= sin%/2cos%
= 1/2(tan%)
the ratio of the height to the range of a projectile is always given by half the tangent of the angle made by the projectile with the horizontal.
Nb:here % is taken insted of symbol theta