$F e S O_{4}$ reacts with ammonium hydroxide to give dirty green precipitate of metallic hydroxide which is insoluble in excess of $N H_{4} O H$ . Name this precipitate.

Fe(OH)₂

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Fe(OH)₃

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Fe(OH)₄

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NaOH

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Solution

The correct option is A
Fe(OH)₂

$F e S O_{4}$ reacts with ammonium hydroxide to give ammonium sulphate along with dirty green precipitate of $F e (O H)_{2}$ which is insoluble in excess of $N H_{4} O H$ .

$F e S O_{4} + 2 N H_{4} O H \to (N H_{4})_{2} S O_{4} + F e (O H)_{2} ↓$

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$F e C l_{3}$ reacts with ammonium hydroxide to give a reddish brown precipitate of metallic hydroxide which is insoluble in excess of $N H_{4} O H$ . Name this precipitate.

When lead nitrate reacts with ammonium hydroxide, a chalky white precipitate is formed. The precipitate formed is insoluble in excess of ammonium hydroxide. Name this precipitate.

Q. Three cations

A, B, C

are allowed to react with ammonium hydroxide solution.

A

and

B

produce a dirty green precipitate and a reddish brown precipitate respectively, both of which do not dissolve on further addition of

{N H}_{4} O H

C

gives pale blue colour precipitate with less amount of ammonium hydroxide and on further addition of

{N H}_{4} O H

, precipitate becomes soluble and deep blue colour solution is formed:

Q. (a) Sodium hydroxide solution is added to solution A. A white precipitate is formed which is insoluble in excess sodium hydroxide solution. Name the metal ion present in solution A.
(b) When ammonium hydroxide is added to solution B, a pale blue precipitate is formed. This pale blue precipitate dissolves in excess ammonium hydroxide to give an inky blue solution. Name the cation present in solution B. What is the probable colour of solution B?

When a green coloured compound reacts with ammonium hydroxide, a dirty green ppt. is formed along with ammonium sulphate. The precipitate formed is:

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FeSO4 reacts with ammonium hydroxide to give dirty green precipitate of metallic hydroxide which is insoluble in excess of NH4OH . Name this precipitate.

The correct option is A Fe(OH)2 FeSO4 reacts with ammonium hydroxide to give ammonium sulphate along with dirty green precipitate of Fe(OH)2 which is insoluble in excess of NH4OH . FeSO4+2NH4OH→(NH4)2SO4+Fe(OH)2↓

$F e S O_{4}$ reacts with ammonium hydroxide to give dirty green precipitate of metallic hydroxide which is insoluble in excess of $N H_{4} O H$ . Name this precipitate.

The correct option is A
Fe(OH)₂

$F e S O_{4}$ reacts with ammonium hydroxide to give ammonium sulphate along with dirty green precipitate of $F e (O H)_{2}$ which is insoluble in excess of $N H_{4} O H$ .

$F e S O_{4} + 2 N H_{4} O H \to (N H_{4})_{2} S O_{4} + F e (O H)_{2} ↓$