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Stoichiometric Calculations

Find the amou...

Question

Find the amount of oxygen required for the complete combustion of 4 mol of butane.
$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$

832 g

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416 g

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280 g

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530 g

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Solution

The correct option is A $832 g$
$2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O$

2 mol of $C_{4} H_{10}$ require 13 mol of $O_{2}$
So, 4 mol of $C_{4} H_{10}$ will require = $\frac{13}{2} \times 4$ = 26 mol of $O_{2}$

Mass of oxygen required = $26 mol \times 32 g/mol$
Mass of oxygen required = $832 g$

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Similar questions

2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O

90 d m^{3}

2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O

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2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O

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C O_{2}

2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O

58 g

158.4 g

C O_{2}

2 C_{4} H_{10} + 13 O_{2} \to 8 C O_{2} + 10 H_{2} O

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