Find the area of each of the following figure, all dimensions are in meters

$\left(1\right)$ Area of the $\Delta DEI=1/2$ $\times$ Base $\times$ Height

$\Rightarrow 1/2\times 60\times 40$

$=1200m^2$

$\left(2\right)$ Area of the Trapezium $EFGI=1/2\times$ $($Sum of the two parallel sides$)$ $\times$ Height

$\Rightarrow 1/2\times (60+50)\times 70$

$\Rightarrow 1/2\times 110\times 70$

$=3850m^2$

$\left(3\right)$ Area of the $\Delta AFG=1/2$ $\times$ Base $\times$ Height

$\Rightarrow 1/2\times 50\times 50$

$=1250m^2$

$\left(4\right)$ Area of the Trapezium$ABCH=1/2$ $\times ($Sum of the two parallel sides$)$ $\times$ Height

$\Rightarrow 1/2\times (40+30)\times 80$

$\Rightarrow 1/2\times 70\times 80$

$=2800sqm$

$\left(5\right)$ Area of the$\Delta CDH=$ $1/2\times$ Base $\times$ Height

The height of this figure is not clear in the image. I think it is $80m$ and I have assumed it $80m.$

$\Rightarrow 1/2\times 40\times 80$

$=1600m^2$

Total area $=$ Area of $\Delta DEI+$ Area of the Trapezium $EFGI+$ Area of $\Delta AFG+$ Area of Trapezium $ABCH+$ Area of $\Delta CDH$

$\Rightarrow 1200+3850+1250+2800+1600$

$=10700$ $m^2$

So$,$ the area of the figure $ABCDEF$ is $10700m^2$