Find the total number of electrons present in $1.6\text{g}$ of $C{H}_4$.

The correct option is A $6.023\times {10}^{23}$ electrons
Molar mass of $C{H}_4=16\text{g/mol}$
Electrons in a molecule of $C{H}_4=6+(1\times 4)=10$
$16\text{g}$ of $C{H}_4$ contains $=10\times 6.023\times {10}^{23}$ electrons
Hence, $1.6\text{g}$ of $C{H}_4$ will contain $=\frac{10\times 6.023\times {10}^{23}\times 1.6}{16}=6.023\times {10}^{23}$ electrons