Given that nbsp-i is angle of incidence and nbsp-r is angle of refraction for a light ray at a boundary- the correct expression for Snell-s Law is- nbsp- sin i- nbsp- sin-2 r-sin i- k sin r-where k - constant- nbsp- nbsp-cos nbsp-i- k cos r-k - constant- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- nbsp- sin r nbsp- nbsp- sin-2 i-

The correct option is B sin i= k sin r [where k = constant] nbsp; nbsp; Snell’s law states that the nbsp;ratio of sine of angle of incidence to the sine ...

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Standard X

Physics

Laws of Refraction

Given that ...

Question

Given that i is angle of incidence and r is angle of refraction for a light ray at a boundary, the correct expression for Snell's Law is:

$sin i = {sin}^{2} r$

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$sin i = k sin r$
[where k = constant]

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$cos i = k cos r$
[k = constant]

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$sin r = {sin}^{2} i$

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Solution

The correct option is B
$sin i = k sin r$
[where k = constant]

Snell’s law states that the ratio of sine of angle of incidence to the sine of angle of refraction is a constant known as refractive index.

$\frac{sin i}{sin r} = k$
where k is a constant and is called refractive index of the medium.

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Similar questions

Given that i is angle of incidence and r is angle of refraction for a light ray at a boundary, the correct expression for Snell's Law is:

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Given that i is angle of incidence and r is angle of refraction for a light ray at a boundary, the correct expression for Snell's Law is:

The correct option is B sini=ksinr [where k = constant] Snell’s law states that the ratio of sine of angle of incidence to the sine of angle of refraction is a constant known as refractive index. sinisinr=k where k is a constant and is called refractive index of the medium.