How many molecules and atoms of sulphur are present in 0.1 moles of $S_8$ molecule?

1 mole of $S_8$ molecules $=6.023\times {10}^{23}$ molecules of $S_8$
Therefore 0.1 mole of $S_8$ molecule $=0.1\times 6.023\times {10}^{23}$ molecules of $S_8=6.023\times {10}^{22}$ molecules of $S_8$
Also, 1 molecules of $S_8$ = 8 atoms of sulphur
$6.023\times {10}^{22}$ molecules of $S_8=8\times 6.023\times {10}^{22}$ atoms of sulphur
$=4.82\times {10}^{23}$ atoms of sulphur.