How many moles of molecules and atoms of sulphur are present in 0.1 mole of $S_8$?

The correct option is D

$8\times 6.022\times {10}^{22}$

1 mole of $S_8$ molecules = $6.022\times {10}^{23}$

0.1 mole of $S_8$ molecules = $6.022\times {10}^{23}\times 0.1=6.022\times {10}^{22}$

1 mole of $S_8$ = 8 atoms

$6.022\times {10}^{23}\times 0.1$ molecules of $S_8$ = $8\times 6.022\times {10}^{23}\times 0.1$ atoms of $S_8$

= 48.176 $\times {10}^{22}$