Identify the gas evolved when:
(i) Potassium sulphite is treated with dilute hydrochloric acid.

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Solution

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.
Reaction involved is:
$K_{2} S O_{3} + 2 H C l \to 2 K C l + H_{2} O + S O_{2} ↑$

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Identify the gas evolved when: (i) Potassium sulphite is treated with dilute hydrochloric acid.

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water. Reaction involved is: K2SO3+2HCl→2KCl+H2O+SO2↑

Identify the gas evolved when:
(i) Potassium sulphite is treated with dilute hydrochloric acid.

When potassium sulphite is treated with dilute hydrochloric acid, sulphur dioxide gas is evolved along with potassium chloride and water.
Reaction involved is:
$K_{2} S O_{3} + 2 H C l \to 2 K C l + H_{2} O + S O_{2} ↑$