Elimination Method of Finding Solution of a Pair of Linear Equations
If
6
kg...
Question
If 6 kg of sugar and 5 kg of tea together cost Rs. 209 and 4 kg of sugar and 3 kg of tea together cost Rs. 131, then the cost of 1 kg sugar and 1 kg tea are respectively
A
Rs. 11 and Rs. 25
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B
Rs. 12 and Rs. 20
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C
Rs. 14 and Rs. 20
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D
Rs. 14 and Rs. 25
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Solution
The correct option is A Rs. 14 and Rs. 25 Let the price of sugar be x and tea be y. Then,
6x+5y=209....(1) 4x+3y=131....(2) Multiply equation (1) by 4 and equation (2) by 6 and then subtract:
(6x+5y=209)4
(4x+3y=131)6
.............................................
24x+20y−24x−18y=209×4−131×6 ............................................. 2y=836−786 2y=50 y=25 Therefore, x=14 Price of sugar is Rs.14 and price of tea is Rs.25 .