If sin-A-cos-A-4-7- then what is the value of 7-sin-A - 3-cos-A-7-sin-A - 2-cos-A- -1-62-122-63-9

The correct options are A 1/6 B 2/12sin A:cos A=4:7 sin A/cos A=4/7 7 sin A 3 cos A/7 sin A + 2 cos A =7 sin A/cos A 3/7 sin A/cos A+2 =7 ( 4/7 ) 3/7 ( 4/ ...

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Byju's Answer

Standard IX

Mathematics

Trigonometric Ratios

If sin A:cos ...

Question

If $s i n A : c o s A = 4 : 7$ , then what is the value of $\frac{7 s i n A - 3 c o s A}{7 s i n A + 2 c o s A}$ ?

\frac{1}{6}

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\frac{2}{12}

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\frac{2}{6}

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\frac{3}{9}

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Solution

The correct options are
A $\frac{1}{6}$
B $\frac{2}{12}$
$s i n A : c o s A = 4 : 7$

$\frac{s i n A}{c o s A} = \frac{4}{7}$

$\frac{7 s i n A - 3 c o s A}{7 s i n A + 2 c o s A}$

$= \frac{7 \frac{s i n A}{c o s A} - 3}{7 \frac{s i n A}{c o s A} + 2}$

$= \frac{7 (\frac{4}{7}) - 3}{7 (\frac{4}{7}) + 2}$

$= \frac{4 - 3}{4 + 2}$

$= \frac{1}{6}$

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If sin A:cos A=4:7, then what is the value of 7 sin A−3 cos A7 sin A+2 cos A?

The correct options are A 16 B 212sin A:cos A=4:7 sin Acos A=47 7 sin A−3 cos A7 sin A+2 cos A =7sin Acos A−37sin Acos A+2 =7(47)−37(47)+2 =4−34+2 =16

If $s i n A : c o s A = 4 : 7$ , then what is the value of $\frac{7 s i n A - 3 c o s A}{7 s i n A + 2 c o s A}$ ?