If the equation for the angular displacement of a particle moving on a circular path is given by - - - 2t-3 - 0-5- where - - is in radians and - t- in seconds- then find the angular velocity of the particle after - 2- seconds from its start-

Angular displacement, θ=2t^3+0.5 Angular velocity, ω=dθdt θ=6t^2 At t=2 seconds ω_t=2=6× 4=24 rad/s ...

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Angular Velocity

If the equati...

Question

If the equation for the angular displacement of a particle moving on a circular path is given by $(θ) = 2 t^{3} + 0.5$ , where $θ$ is in radians and $t$ in seconds, then find the angular velocity of the particle after $2$ seconds from its start.

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(θ) = 2 t^{3} + 0.5

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θ = 2 t^{3} + 0.5

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θ = 2 t^{3} + 0.5

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θ = 2 t^{3} + 0.5

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θ = 0.025 t^{2} - 0.1 t

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