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Refractive Index

If the index ...

Question

If the index of refraction of diamond is $2.0$ , velocity of light in diamond in cm/second is approximately.

6 \times 10^{10}

cm/s

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3.0 \times 10^{10}

cm/s

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2 \times 10^{10}

cm/s

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1.5 \times 10^{10}

cm/s

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Solution

The correct option is D $1.5 \times 10^{10}$ cm/s
$μ_{m e d i u m} =$ velocity of light in vaccuum/velocity of light in the medium
So, velocity of light in diamond
$\frac{3 \times 10^{10}}{2} c m s^{- 1} = 1.5 \times 10^{10}$ $c m s^{- 1}$

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