If the momentum of a body is increased by 100 -200 -225 -300 -

The correct option is D 300 E=P^2/2m⇒E_2/E_1= ( P_2/P_1 )^2= ( 2P/P )^2=4 E_2=4E_1=E_1+3E_1=E_1+300 % of E_1 ...

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The 'e' Equation

If the moment...

Question

If the momentum of a body is increased by 100 %, then the percentage increase in the kinetic energy is

150 %

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200 %

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225 %

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300 %

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Solution

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