If three neutrons are added to the nuclei of ${}_{92}{U}^{235}$, the new nucleus will have an atomic number of

Q. After emission of an plane particle from ${}_{92}{U}^{238}$ nucleus, the number of neutrons in the new nucleus are:

Q. A plot of the number of neutrons ($N$) against the number of protons ($P$) of stable nuclei exhibits upward deviation from linearity for atomic number, $Z>20$. For an unstable nucleus having $\frac{N}{P}$ ratio less than 1, the possible mode(s) of decay is/are

Q. Assertion :Light nuclei are most stable if $N=Z$, while heavy nuclei are more stable if $N>Z$. ($N\to$ number of neutrons, $Z\to$ number of protons). Reason: As the number of protons increases in a nucleus, the Coulomb's repulsive force increases, which tends to break the nucleus apart. So, to keep the nucleus stable, more number of neutrons are needed which are neutral in nature.

Q. A plot of the number of neutrons (n) against the number of protons (p) of stable nuclei exhibits upward deviation from linearity for atomic number, Z> 20. For an unstable nucleus having n/p ratio less than 1, the possible mode(s) of decay is (are)

Q. Constituents of nucleus of three atoms A, B and C are given below:
A - 90 protons and 148 neutrons
B - 92 protons and 146 neutrons
C - 90 protons and 146 neutrons
Based on the above data, which of these atoms are isotopes.