If $V$ ml of the vapours of substance at NTP weighs $W$ g. Then, molecular weight of substance is :

Q. A $5\%$ w/v solution of cane sugar is isotonic with $1\%$ w/v solution of a substance 'x'. The molecular weight of 'x' is ( in g/mol):

Q. $5\%\left(w/v\right)$ solution of glucose is isotonic with $2\%\left(w/v\right)$ solution of a non-volatile non electrolyte substance at same ‘T’. The molecular mass of the substance will be:
[0.77 Mark]

Q. A sugar solution is $10$ (w/v). Find (w/v%) if density of solution is $1.25g/ml$.

Q. Let $\overrightarrow{u},\overrightarrow{v},\overrightarrow{w}$ be such that $|\overrightarrow{u}|=1,|\overrightarrow{v}|=2,|\overrightarrow{w}|=3$. If the projection of $\overrightarrow{v}$ along $\overrightarrow{u}$ is equal to that of $\overrightarrow{w}$ along $\overrightarrow{u}$ and $\overrightarrow{v},\overrightarrow{w}$ are perpendicular to each other then $|\overrightarrow{u}-\overrightarrow{v}+\overrightarrow{w}|$ equals

Q. Let u,v,w be such that |u|=1, |v|=2, |w|=3. If the projection v along u is equal to that of w along u and v, w are perpendicular to each other then |u-v+w| =