If we throw a body vertically upwards with velocity of 4 m/s. Then at what height does its kinetic energy reduce to half of initial value?(Take g=10 m/s^-2)

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Solution

we know that the total energy of a body remains conserved......so initial energy = final energy.......initially we will only have kinetic energy and zero potential energy.....at some height the KE becomes half along with some potential energy,,,,,,, ...KE = 0.5KE + PE... ...0.5KE = MgH... ...0.25 x M x V x V = M x g x H...initial velocity V = 4m/s... ...0.25 x 16 = 10 x H... ...H = 0.4 metres

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If we throw a body vertically upwards with velocity of 4 m/s. Then at what height does its kinetic energy reduce to half of initial value?(Take g=10 m/s-2)

If we throw a body vertically upwards with velocity of 4 m/s. Then at what height does its kinetic energy reduce to half of initial value?(Take g=10 m/s^-2)