In a pseudo first order acid catalysed hydrolysis of ester in water the following results were obtained:
t/s 0 30 60 90
[ester]/M 0.55 0.31 0.17 0.085
Which of the following is/are correct for the given reaction?

The average rate of reaction between time interval 30 to 60 seconds is

4.67 \times 10^{- 3} m o l L^{- 1} s^{- 1}

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Order of reaction is 2.

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Pseudo first order rate constant for the acid catalysed hydrolysis of ester is

1.92 \times 10^{- 2} s^{- 1}

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All are correct.

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Solution

The correct options are
A The average rate of reaction between time interval 30 to 60 seconds is $4.67 \times 10^{- 3} m o l L^{- 1} s^{- 1}$
C Pseudo first order rate constant for the acid catalysed hydrolysis of ester is $1.92 \times 10^{- 2} s^{- 1}$
$r a t e_{a v g} = 0.14 / 30 = 4.67 \times 10^{- 3}$
$∴ k = 1.92 \times 10^{- 2}$

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Similar questions

Q. In a pseudo first order hydrolysis of ester in water the following results were obtained:

$t / s$	$0$	$30$	$60$	$90$
$[E s t e r] / M .$	$0.55$	$0.31$	$0.17$	$0.085$

(i) Calculate the average rate of reaction between the time interval

30

60

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(ii) Calculate the pseudo first order rate constant for the hydrolysis of ester.

In a pseudo first order hydrolysis of ester in water, the following results were obtained:

t/s	0	30	60	90
[Ester]mol L⁻¹	0.55	0.31	0.17	0.085

(i) Calculate the average rate of reaction between the time interval 30 to 60 seconds.

(ii) Calculate the pseudo first order rate constant for the hydrolysis of ester.

In a pseudo first order hydrolysis of ester in water, the following results were obtained:
$\begin{matrix} t / s & 0 & 30 & 60 & 90 [E s t e r] / m o l L^{- 1} & 0.55 & 0.31 & 0.17 & 0.085 \end{matrix}$
Calculate the average rate of reaction between the time interval 30 to 60 s.

$\begin{matrix} t / s & 0 & 30 & 60 & 90 [E s t e r] / m o l L^{- 1} & 0.55 & 0.31 & 0.17 & 0.085 \end{matrix}$
Calculate the psuedo first order rate constant for the hydrolysis of ester.

Q. In a pseudo first order hydrolysis of ester, the following results were obtained:

t in s	0	30	60	90
[Ester] in mol $L^{- 1}$	0.55	0.31	0.17	0.085

Calculate the average rate of reaction between the time interval 30 to 60 seconds.

Q. In a pseudo first order hydrolysis of ester in water, the following results were obtained.What will be the average rate of reaction between the time interval

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In a pseudo first order acid catalysed hydrolysis of ester in water the following results were obtained:t/s 0 30 60 90[ester]/M 0.55 0.31 0.17 0.085Which of the following is/are correct for the given reaction?

The correct options are A The average rate of reaction between time interval 30 to 60 seconds is 4.67×10−3molL−1s−1 C Pseudo first order rate constant for the acid catalysed hydrolysis of ester is 1.92×10−2s−1rateavg=0.14/30=4.67×10−3∴k=1.92×10−2

In a pseudo first order acid catalysed hydrolysis of ester in water the following results were obtained:
t/s 0 30 60 90
[ester]/M 0.55 0.31 0.17 0.085
Which of the following is/are correct for the given reaction?