In a typical Indian Bugghi (a luxury cart drawn by horses), a wooden plate is fixed on the rear on which one person can sit. A bugghi of mass 200kg is moving at a spped of 10km/h. As it overtakes a school boy walking at a speed of 4 km/h, the boy sits on the wooden plate. If the mass of the boy is 25kg, what will be the new velocity of the bugghi?

6 km/hr

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9.33 km/hr

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12.63 km/hr

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none ot these

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Solution

The correct option is B 9.33 km/hr
Mass of the boggli = 200kg, $V_{B} =$ 10 km/hour.
$∴$ Mass of the boy = 2.5kg & $V_{B o y}$ = 4km/hour.
If we take the boy & boggle as a system then total momentum before the process of sitting will remain constant after the process of sitting.
$∴ m_{b} V_{b} = m_{b o y} V_{b o y} = (m_{b} + m_{b o y}) v$
$\Rightarrow 200 \times 10 + 25 \times 4 = (200 + 25) \times v$
$\Rightarrow v = \frac{2100}{225} = \frac{28}{3} = 9.3 m / s e c$

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