In Dumas method for estimation of nitrogen 30g of an organic compound gave 50ml of nitrogen collected at 300k temperature and 715mm pressure. Find the $%$ of nitrogen in the given compound.

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Solution

We know that aqueous tension of water at 300 K is 15 mm.
Mass of the subs = 30g
Vol. of $N_{2}$ = 50 ml
Room temp = 300 K
Vapour pressure of water at 300K = 15 mm
Actual pressure (dry gas) = 715 - 15 = 700 mm Hg.
Convert the Vol. at experimental conditions to vol at stp.
$\frac{P_{1} V_{1}}{T_{1}} = \frac{P_{2} V_{2}}{T_{2}}$
$= 41.9 c m^{3}$
Convert the volue at spt into mass
$222400 c m^{3}$ of $N_{2}$ at STP weights 28 g.
$41.9 c m^{3}$ would weigh
$28 \times \frac{41.9}{22400} g$
$%$ of $N_{2}$ .
Mass of $N_{2}$ at $\frac{S T P}{M a s s o f t h e s u b s t a n c e t a k e n} \times 100$
$\frac{28 \times 41.9 \times 100}{22400 \times 0.3} = 17.46$ $%$

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