In the given circuit, when the switch is closed, the capacitor charges with a time constant of

Q. In the circuit shown in figure, when the switch is closed, the capacitor charges with a time constant

Q. Three capacitors (of capacitances C, 2C and 3C) and three resistors (of resistance R, 2R and 3R) are connected with a battery and switch S as shown in the figure. When switch S is open, charges on the capacitors are shown. Switch S is closed at t =0 sec. The time constant of the circuit will be

Q.
In a given circuit, switch S was closed for a long time and is opened in an instant. Charge on capacitor after time $t=\frac{\pi }{1200}sec$ after opening the switch is

Q. Each capacitors in the circuit of given figure is $4\mu F$. When the switch S is closed how much charge will flow through AB?

Q. Consider the circuit shown in figure. When switch $S_1$ closed and the other two switches open, the circuit has a time constant $0.05\text{sec}$. When switch $S_2$ closed and the other two switches open, the circuit has a time consatnt $2\text{sec}$. When switch $S_3$ closed an the other two switches open,the circuit oscillates with a period $T$. Find $T(\text{in sec). Take}{\pi }^2=10$