Jim needs to rent a car. A rental company charges $$ 21.00$ per day to rent a car and $$ 0.10$ driven. for every mile.
He will travel $250$ miles.
He has $$ 115.00$ to spend.
Write an inequality that can be used to determine $$ 115.00$ , the maximum number of days that Jim can rent a car.

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Solution

Step-1: Write the information given in the question:
The fixed charge of the rental company is $$ 21.00$ per day.
The additional cost is $$ 0.10$ for every mile.
Jim travels $250$ miles.
The amount Jim has to spend is $$ 115.00$ .
Step-2: Find the value of $d .$
Let the number of days for which Jim rents the car is $d .$
Thus, according to the question,
$21 d + 25 < 115 \Rightarrow 21 d < 115 - 25 \Rightarrow 21 d < 90 \Rightarrow \frac{21 d}{21} < \frac{90}{21} \Rightarrow d < 4.3 ∴ d = 4$
Hence, Jim can rent the car for maximum $4$ days.

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Jim needs to rent a car. A rental company charges $21.00 per day to rent a car and $0.10 driven. for every mile. He will travel 250 miles. He has $115.00 to spend. Write an inequality that can be used to determine $115.00, the maximum number of days that Jim can rent a car.

Jim needs to rent a car. A rental company charges $$ 21.00$ per day to rent a car and $$ 0.10$ driven. for every mile.
He will travel $250$ miles.
He has $$ 115.00$ to spend.
Write an inequality that can be used to determine $$ 115.00$ , the maximum number of days that Jim can rent a car.