$K O H_{(a q)} + H_{3} P O_{4 (a q)} \to K_{3} P O_{4 (a q)} + H_{2} O_{(l)}$
When the equation for the reaction represented above is balanced and the coefficients are reduced to the lowest whole number terms, the coefficient for $H_{2} O$ is:

1

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2

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3

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4

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Solution

The correct option is C $3$
The balanced equation can be written as
$3$ $K O H$ $+$ $H_{3} P O_{4}$ $=$ $K_{3} P O_{4}$ $+$ $3 H_{2} O$
Thus the coefficient of $H_{2} O$ is 3
Option C is the correct answer.

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