Medicine is packed in boxes, each weighing $4 kg 500 gm$ . How many such boxes can be loaded in a can which cannot carry beyond $800 kg$ ?

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Solution

Step 1: Convert $grams$ into $kilograms$ .
The weight of one box in $kilograms$ :
$\begin{array}{l} 4 kg 500 gm \\ = 4 kg + \frac{500}{1000} kg \\ = 4 kg + 0.5 kg \\ = 4.5 kg \end{array} [1 kg = 1000 gm \Rightarrow 1 gm = \frac{1}{1000} kg]$
Step 2: Calculate the number of boxes
The total weight allowed $= 800 kg$
Therefore, the number of boxes required:
$\begin{array}{l} \frac{Total Weight}{Weight of one box} \\ = \frac{800}{4.5} \\ = 177.77 \\ \approx 177 \end{array}$
Hence, the total number of boxes that can hold $800 kg$ is $177$ .

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