The mass defect for the nucleus of helium is $0.0302\text{amu}$. The binding energy per nucleon for helium in $\text{MeV}$ is approximately.
$(1\text{amu}=930\frac{\text{MeV}}{c^2})$

Q. Mass defect for the helium nucleus is $0.0303amu$. Binding energy per nucleon for this (in $MeV$) will be_______

Q. Binding energy per nucleon for helium nucleus ${(}_2^{4}He)$ is 7.0 MeV. Find vallue of mass defect for helium nucleus.

Q.

The masses of neutron and proton are 1.0087 amu and 1.0073 amu respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 amu, the binding energy of the helium nucleus will be [1 amu= 931 MeV]

Q. The masses of neutron and proton are $1.0087$amu. and $1.0073$ amu. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass $4.0015$ amu. the binding energy for the helium nucleus will be ($1$ a.m.u = $931$ MeV)

Q. Two deuterons undergo nuclear fusion to form a Helium nucleus. Energy released in this process is : (given binding energy per nucleon for deuteron $=1.1MeV$ and for helium $=7.0MeV$)