A solid is made of two elements P and Q. Atoms P are in ccp arrangement and atom Q occupy all octahedral voids and half of tetrahedral voids. The simplest formula of the compound is :-

P Q_{4}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P_{2} Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

P Q_{2}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

P Q

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $P Q_{2}$
As we know no of atoms in ccp (Z) is 4 therefore $P = 4$ and we know no. of octahedral voids are 4 and total tetrahedral voids are 8 but according to question Q occupy all octahedral and half tetrahedral voids, therefore $Q = 4 + 4 = 8$ , so formula will be $P_{4} Q_{8}$ or we can write $P Q_{2}$ .

Suggest Corrections

Similar questions

A compound formed by elements X, Y, Z . Atoms of Y forms ccp lattice and X occupies half the octahedral voids and Z occupies half the tetrahedral voids. Find the formula of the compound?

Q. A crystalline solid between A and B has the following arrangement of atoms:
(i) Atoms A are arranged in a CCP array.
(ii) Atoms B occupy all the octahedral voids and half of the tetrahedral voids.
What is the formula of the compound?

Q. A crystalline solid is made of two elements A and B. An ions of B are arranged in ccp lattice and cations of A occupy half of octahedral and half tetrahedral voids . formula of the solid is :

Q. Element

B

forms ccp structure and

A

occupies half of the octahedral voids, while oxygen atoms occupy all the tetrahedral voids. The formula of bimetallic oxide is:

Q. A crystalline solid is made of X, Y and Z. Atoms of X are present in ccp lattice; Y occupies all the octahedral voids and Z occupies all the tetrahedral voids. If all atoms along one body diagonal are removed then the simplest formula of solid will be:

Join BYJU'S Learning Program

A solid is made of two elements P and Q. Atoms P are in ccp arrangement and atom Q occupy all octahedral voids and half of tetrahedral voids. The simplest formula of the compound is :-

The correct option is C PQ2As we know no of atoms in ccp (Z) is 4 thereforeP=4 and we know no. of octahedral voids are 4 and total tetrahedral voids are 8 but according to question Q occupy all octahedral and half tetrahedral voids, therefore Q=4+4=8, so formula will be P4Q8 or we can write PQ2.