ntA nuclei of mass 220 amu in free state decays to emit an alpha particle.Kinetic energy of the alpha particle emitted is 5.4 MeV.The recoil energy of the daughter nucleus isn

Q. A nucleus of mass 218 amu in free state decays to emit an $\alpha$ particle. Kinetic energy of the $\alpha$ particle emitted is 6.7 MeV. The recoil energy (in MeV) of the daughter nucleus is:

Q. A stationary Thorium nucleus $(A=220,Z=90)$ emits an alpha particle with kinetic energy $E_{\alpha }$. What is the kinetic energy of the recoiling nucleus?

Q. A stationary $P{b}^{200}$ nucleus emits an $\alpha -$particle with certain kinetic energy $K_{\alpha }$. If recoil velocity of daughter nucleus is $3.39\times 105m/s$ and $f$ is the fraction of the total energy liberated in this decay which is accounted for the recoil energy of the daughter nuclei, then

Q. A nucleus at rest undergoes $\alpha -decay$ emitting an $\alpha -particle$ of de Broglie wavelength $\lambda =5.76\times {10}^{-15}$ m. If the mass of the daughter nucleus is 223.610 amu and that of the $\alpha -particle$ is 4.002 amu, determine the total kinetic energy in the final state, Hence, obtain the mass of parent nucleus in amu. $(1amu=931.470MeV{c}^{-2})$

Q. A stationary $P{b}^{200}$ nucleus emits an alpha-particle with kinetic energy $K_{\alpha }$. The fraction of recoil energy of the daughter nucleus to the total energy liberated is :