ntP2O5 on treatment with exces s of H2O followed by excess of NH4OH forms (NH4)2HPO4. If hundred gram of (NH4)2HPO4 is formed then find out the mass of p 2 o5 initial takenn

Q. In diammonium phosphate $(N{H}_4{)}_{2}HP{O}_4$, the percentage of $P_2{O}_5$ is :

Q. In diammonium phosphate, $(N{H}_4{)}_{2}HP{O}_4$, the percentage of $P_2{O}_5$ is

Q. The percentage of $P_2{O}_5$ in diammonium hydrogen phosphate, $\left[\right(N{H}_4{)}_{2}HP{O}_4]$ is:

Q. A black coloured sulphide is formed on passing $H_{2}S$ through a solution of a compound $‘X^{\prime }$ in $N{H}_{4}OH$. $‘X^{\prime }$ on treatment with cyanide gives a buff-coloured precipitate, which dissolves in excess of this reagent forming compound $‘Y^{\prime }$. The solution of $‘X^{\prime }$ was treated with excess of $NaHC{O}_3$ and then with $B{r}_2$-water. On cooling and shaking for sometime, a green coloured compound $‘Z^{\prime }$ is formed.