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Question

Number of orbitals possible for n=3 energy shell is ______.

A

3
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B

5
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C

7
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D

9
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Solution

The correct option is D
9
n=3(third energy shell)l=n1=31=2i.e.,l=0,1,2


l = 0, s-subshell-3s = 1 orbital(3s)

l =1, p-subshell-3p = 3 orbitals(3px,3py,3pz)

l = 2, d-subshell-3d = 5 orbitals(3dxy,3dyz,3dxz,3dx2y2,3dz2)

The total number of orbitals is equal to 1+3+5=9.

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