On Reaumer scale of temperature the melting point of ice and the boiling point of water are taken as 0R and 80R respectivel. The freezing point and boiling point of mercury on Celsius scale are 39C and 367C respectively. Express these temperature on Reaumer scale.

Q. On a new scale of temperature (which is linear) and called the W scale, the freezing and boiling points of water are 39°W and 239°W respectively. What will be the temperature on the new scale, corresponding to a temperature of 39°C on the Celsius scale ?

Q. On a new scale of temperature (which is linear) and called the \(W\) scale, the freezing and boiling points of water are \(39^{\circ}~W\) and \(239^{\circ}~W\) respectively. What will be temperature in \(~^{\circ}~W\) on the new scale, corresponding to a temperature of \(39^{\circ}~C\) on the Celsius scale?

Q. For a new scale of temperature called ${}^{\circ }P$ scale (which is linear and total division of the new scale is 200) the freezing and boiling points of water are ${25}^{\circ }P$ and ${225}^{\circ }P$ respectively. Then the temperature on new scale corresponding to ${25}^{\circ }C$ on the celsius scale is :

Q. The scale of temperature where the melting point of ice is $0^o$ and the boiling point of water is taken as ${100}^o$ is

Q. In a scientific book that describes a temperature scale called $Z$, boiling and freezing point of water are referred as ${65}^{o}Z$ and $-{15}^{o}Z$ respectively. (a) To what temperature on Fahrenheit scale would a temperature $-{95}^{o}Z$ compound? (b) What temperature change on the $Z$ scale that would correspond to a change of ${40}^o$ on Celsius scale?