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Question

One mole of any substance contains 6.022×1023 atoms/molecules. Number of molecules of H2SO4 present in 100 mL of 0.02M H2SO4 solution is ___.

A
12.044×1020 molecules
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B
1×1023 molecules
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C
12.044×1023 molecules
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D
6.022×1023 molecules
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Solution

The correct option is A 12.044×1020 molecules
Calculating the number of moles of H2SO4

Given:

1 mole of substance contains 6.022×1023 molecules.

Volume of solution = 100 mL = 0.1 L
Molarity of solution = 0.02 M

We Know,

Molarity = number of moles of soluteVolume of solution (in L)

no. of moles of solute = molarity × volume
=0.02 mol L1×0.1 L
= 0.002 mol

Calculating the number of molecules of H2SO4

Number of molecules of H2SO4
= number of moles × 6.022×1023
=0.002×6.022×1023
= 12.044×1020 molecules

Thus, 12.044×1020 molecules of H2SO4 are present in 100 mL of 0.02 M H2SO4 solution.

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