Oxidation states of chlorine in the products when chlorine reacts with hot and conc. NaOH are:

-1, + 1

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-1, + 3

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-1, + 5

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-1, + 7

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Solution

The correct option is B -1, + 5
$C l_{2} + 2 N o O H (c o n c) h o t \to N a - 1 C l + N a {+ 5 C l O}_{3}$
In $N a C l$ the oxidation state of Na is +1 thus oxidation state of chlorine is -1.
In $N a C l O_{3}$ the oxidation state of Na is +1 and that of oxygen is -2. Thus oxidation state of Cl will be +5.

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Oxidation states of chlorine in the products when chlorine reacts with hot and conc. NaOH are:

The correct option is B -1, + 5Cl2+2No OH(conc)hot→Na−1Cl+Na+5ClO3In NaCl the oxidation state of Na is +1 thus oxidation state of chlorine is -1.In NaClO3 the oxidation state of Na is +1 and that of oxygen is -2. Thus oxidation state of Cl will be +5.