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Solving Linear Equations Using Transpose of Terms

Reena has eno...

Question

Reena has enough money to buy $10 k g$ of potatoes worth $R s 18 / k g$ with the same money. How much kilograms of potatoes can she buy if the price of potatoes increases to $R s 20 / k g$

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Solution

Que. Reena has money to buy 10 kg potatoes at rate
Rs 18/kg.
$\to M o n e y = 10 \times 18$
$180 R s .$
$\to$ at rate 20 Rs/kg.
Money = rate $\times$ weight
$180 = 20 \times$ weight
weight $= \frac{180}{20}$
= 9 kg
Reena buy 9 kg of potatoes If price increase to 20/kg.

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