Refraction takes place at a convex spherical boundary separating air-glass medium. For the image to be real, the object distance $({\mu }_g=\frac{3}{2})$

Q. Refraction takes place at a concave spherical boundary $($of radius of curvature $R)$ separating glass - air medium. For the image to be real, the object which is placed in glass at a distance $u$ $({\mu }_{glass}=\frac{3}{2})$

Q. A convex refracting surface of radius of curvature 20 cm separates two media of refractive indices 4/3 and 1.60. An object is placed in the first medium $(\mu =4/3)$ at a distance of 200 cm from the refracting surface. The position of the image formed is

Q. A concave spherical surface of radius of curvature $10\text{cm}$ separates two medium $X$ & $Y$ of refractive index $\frac{4}{3}$ & $\frac{3}{2}$ respectively. If the object is placed along principal axis in medium $X$ then

Q. (a) Derive the mathematical relation between refractive indices $n_1$ and $n_2$ of two media and radius of curvature R for refraction at a convex spherical surface. Consider the object to be a point since lying on the principle axis in rarer medium of refractive index $n_1$ and a real image formed in the denser medium of refractive index $n_2$. Hence, derive Lens Maker's formula.

(b) Light from a point source in air falls on a convex spherical glass surface of refractive index 1.5 and radius of curvature 20 cm. The distance of light source from the glass surface is 100 cm. At what position is the image formed ?

Q. A spherical surface of radius of curvature $R$ separates air (refractive index 1.0) from glass (refractive index 1.5).The centre of curvature is in the glass. A point object $P$ placed in air is found to have a real image $Q$ in the glass. The line $PQ$ cuts the surface at a point $O\text{and}PO=OQ$.Find the distance of object from the spherical surface.