State the number of images of an object placed between the two plane mirrors, formed in each case when the mirrors inclined to each other at

(a) $90^{\circ} a n d (b) 60^{\circ}$ .

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Solution

(a) Angle between the mirrors, $θ = 90^{o}$

Now, $n = \frac{360^{o}}{θ^{o}} = \frac{360^{o}}{90^{o}} = 4$ , which is even.

Hence number of images formed will be (n-1); i.e., 4 - 1 = 3 images

(b) Angle between the mirrors, $θ = 60^{o}$

Now, $n = \frac{360^{o}}{θ^{o}} = \frac{360^{o}}{60^{o}} = 6$ , which is even.

Hence number of images formed will be (n-1); i.e., 6 - 1 = 5 images

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Similar questions

(a) 90^{\circ}

(b) 60^{\circ}

State the number of images of an object placed between two mirrors inclined at 90^o to each other.

State the number of images of an object placed between two mirrors inclined at 90 degrees to each other.

45^{\circ}

The number of images formed of an object placed between two plane mirrors inclined at right angles to each other is:

(a) two

(b) five

(d) three

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