The absolute refractive index of the diamond is 2.1. What is the velocity of light in a diamond?

1.672 \times 10^{8} m / s

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2.428 \times 10^{8} m / s

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1.428 \times 10^{8} m / s

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2.672 \times 10^{8} m / s

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Solution

The correct option is C $1.428 \times 10^{8} m / s$
Velocity of light in vacuum, $c = 3 \times 10^{8} m / s$
Let the velocity of light diamond be $v_{d}$
Absolute refractive index of diamond is given by:
$μ_{d} = \frac{c}{v_{d}}$
$v_{d} = \frac{c}{μ_{d}}$
$v_{d} = \frac{3 \times 10^{8} m / s}{2.1}$
$v_{d} = 1.428 \times 10^{8} m / s$

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The absolute refractive index of the diamond is 2.1. What is the velocity of light in a diamond?

The correct option is C 1.428×108m/sVelocity of light in vacuum, c=3×108 m/s Let the velocity of light diamond be vd Absolute refractive index of diamond is given by: μd=cvd vd=cμd vd=3×108 m/s2.1 vd=1.428×108 m/s