The amount of carbon dioxide produced when 40 g of methane reacts with 48 g of oxygen is.

The correct option is B 33 g
Gram molecular mass of methane = 16 g
Gram molecular mass of oxygen = 32 g

The balanced chemical reaction between methane and oxygen is as follows:
${\mathrm{CH}}_4\left(g\right)+2O_2\left(g\right)\to {\mathrm{CO}}_2\left(g\right)+2H_{2}O\left(g\right)16g64g44g36g$


Thus, 16 g of methane reacts with 64 g of oxygen to produce 44 g of carbon dioxide.

The amount of oxygen required to react with 40 g of methane = $\frac{64}{16}\times 40=160g$

Since only 48 g of oxygen is present, it will act as a limiting reagent.

The amount of carbon dioxide produced by 48 g of oxygen = $\frac{44}{64}\times 48=33g$