The compound $Z n F e_{2} O_{4}$ is

A normal spinel compound

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Interstitial compound

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Covalent compound

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Co-ordination compound

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Solution

The correct option is A

A normal spinel compound

The compound $Z n F e_{2} O_{4}$ is a normal spinel compound.

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Similar questions

Z n F e_{2} O_{4}

A normal spinel compound

Interstitial compound

Covalent compound

C_{7} H_{8} 3 C l_{2} / Δ - --- \to A B r_{2} / F e - --- \to B Z n / H C l - ---- \to C

C_{7} H_{8} 3 C l_{2} / △ - --- \to X B r_{2} / F e - --- \to Y Z n / H C l - ---- \to Z

Z

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